Optimal. Leaf size=193 \[ 77 c^2 d^{13/2} \left (b^2-4 a c\right )^{3/4} \tan ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt{d} \sqrt [4]{b^2-4 a c}}\right )-77 c^2 d^{13/2} \left (b^2-4 a c\right )^{3/4} \tanh ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt{d} \sqrt [4]{b^2-4 a c}}\right )-\frac{11 c d^3 (b d+2 c d x)^{7/2}}{2 \left (a+b x+c x^2\right )}-\frac{d (b d+2 c d x)^{11/2}}{2 \left (a+b x+c x^2\right )^2}+\frac{154}{3} c^2 d^5 (b d+2 c d x)^{3/2} \]
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Rubi [A] time = 0.148014, antiderivative size = 193, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.269, Rules used = {686, 692, 694, 329, 298, 203, 206} \[ 77 c^2 d^{13/2} \left (b^2-4 a c\right )^{3/4} \tan ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt{d} \sqrt [4]{b^2-4 a c}}\right )-77 c^2 d^{13/2} \left (b^2-4 a c\right )^{3/4} \tanh ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt{d} \sqrt [4]{b^2-4 a c}}\right )-\frac{11 c d^3 (b d+2 c d x)^{7/2}}{2 \left (a+b x+c x^2\right )}-\frac{d (b d+2 c d x)^{11/2}}{2 \left (a+b x+c x^2\right )^2}+\frac{154}{3} c^2 d^5 (b d+2 c d x)^{3/2} \]
Antiderivative was successfully verified.
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Rule 686
Rule 692
Rule 694
Rule 329
Rule 298
Rule 203
Rule 206
Rubi steps
\begin{align*} \int \frac{(b d+2 c d x)^{13/2}}{\left (a+b x+c x^2\right )^3} \, dx &=-\frac{d (b d+2 c d x)^{11/2}}{2 \left (a+b x+c x^2\right )^2}+\frac{1}{2} \left (11 c d^2\right ) \int \frac{(b d+2 c d x)^{9/2}}{\left (a+b x+c x^2\right )^2} \, dx\\ &=-\frac{d (b d+2 c d x)^{11/2}}{2 \left (a+b x+c x^2\right )^2}-\frac{11 c d^3 (b d+2 c d x)^{7/2}}{2 \left (a+b x+c x^2\right )}+\frac{1}{2} \left (77 c^2 d^4\right ) \int \frac{(b d+2 c d x)^{5/2}}{a+b x+c x^2} \, dx\\ &=\frac{154}{3} c^2 d^5 (b d+2 c d x)^{3/2}-\frac{d (b d+2 c d x)^{11/2}}{2 \left (a+b x+c x^2\right )^2}-\frac{11 c d^3 (b d+2 c d x)^{7/2}}{2 \left (a+b x+c x^2\right )}+\frac{1}{2} \left (77 c^2 \left (b^2-4 a c\right ) d^6\right ) \int \frac{\sqrt{b d+2 c d x}}{a+b x+c x^2} \, dx\\ &=\frac{154}{3} c^2 d^5 (b d+2 c d x)^{3/2}-\frac{d (b d+2 c d x)^{11/2}}{2 \left (a+b x+c x^2\right )^2}-\frac{11 c d^3 (b d+2 c d x)^{7/2}}{2 \left (a+b x+c x^2\right )}+\frac{1}{4} \left (77 c \left (b^2-4 a c\right ) d^5\right ) \operatorname{Subst}\left (\int \frac{\sqrt{x}}{a-\frac{b^2}{4 c}+\frac{x^2}{4 c d^2}} \, dx,x,b d+2 c d x\right )\\ &=\frac{154}{3} c^2 d^5 (b d+2 c d x)^{3/2}-\frac{d (b d+2 c d x)^{11/2}}{2 \left (a+b x+c x^2\right )^2}-\frac{11 c d^3 (b d+2 c d x)^{7/2}}{2 \left (a+b x+c x^2\right )}+\frac{1}{2} \left (77 c \left (b^2-4 a c\right ) d^5\right ) \operatorname{Subst}\left (\int \frac{x^2}{a-\frac{b^2}{4 c}+\frac{x^4}{4 c d^2}} \, dx,x,\sqrt{d (b+2 c x)}\right )\\ &=\frac{154}{3} c^2 d^5 (b d+2 c d x)^{3/2}-\frac{d (b d+2 c d x)^{11/2}}{2 \left (a+b x+c x^2\right )^2}-\frac{11 c d^3 (b d+2 c d x)^{7/2}}{2 \left (a+b x+c x^2\right )}-\left (77 c^2 \left (b^2-4 a c\right ) d^7\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{b^2-4 a c} d-x^2} \, dx,x,\sqrt{d (b+2 c x)}\right )+\left (77 c^2 \left (b^2-4 a c\right ) d^7\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{b^2-4 a c} d+x^2} \, dx,x,\sqrt{d (b+2 c x)}\right )\\ &=\frac{154}{3} c^2 d^5 (b d+2 c d x)^{3/2}-\frac{d (b d+2 c d x)^{11/2}}{2 \left (a+b x+c x^2\right )^2}-\frac{11 c d^3 (b d+2 c d x)^{7/2}}{2 \left (a+b x+c x^2\right )}+77 c^2 \left (b^2-4 a c\right )^{3/4} d^{13/2} \tan ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt [4]{b^2-4 a c} \sqrt{d}}\right )-77 c^2 \left (b^2-4 a c\right )^{3/4} d^{13/2} \tanh ^{-1}\left (\frac{\sqrt{d (b+2 c x)}}{\sqrt [4]{b^2-4 a c} \sqrt{d}}\right )\\ \end{align*}
Mathematica [C] time = 0.160206, size = 145, normalized size = 0.75 \[ -\frac{4 d^5 (d (b+2 c x))^{3/2} \left (-16 c^2 \left (77 a^2+55 a c x^2+5 c^2 x^4\right )+1232 c^2 (a+x (b+c x))^2 \, _2F_1\left (\frac{3}{4},3;\frac{7}{4};\frac{(b+2 c x)^2}{b^2-4 a c}\right )+4 b^2 c \left (99 a+25 c x^2\right )-80 b c^2 x \left (11 a+2 c x^2\right )+180 b^3 c x-27 b^4\right )}{15 (a+x (b+c x))^2} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.203, size = 857, normalized size = 4.4 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.90145, size = 2148, normalized size = 11.13 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.27027, size = 703, normalized size = 3.64 \begin{align*} -\frac{77}{2} \, \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{3}{4}} c^{2} d^{5} \arctan \left (\frac{\sqrt{2}{\left (\sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} + 2 \, \sqrt{2 \, c d x + b d}\right )}}{2 \,{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}}}\right ) - \frac{77}{2} \, \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{3}{4}} c^{2} d^{5} \arctan \left (-\frac{\sqrt{2}{\left (\sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} - 2 \, \sqrt{2 \, c d x + b d}\right )}}{2 \,{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}}}\right ) + \frac{77}{4} \, \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{3}{4}} c^{2} d^{5} \log \left (2 \, c d x + b d + \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} \sqrt{2 \, c d x + b d} + \sqrt{-b^{2} d^{2} + 4 \, a c d^{2}}\right ) - \frac{77}{4} \, \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{3}{4}} c^{2} d^{5} \log \left (2 \, c d x + b d - \sqrt{2}{\left (-b^{2} d^{2} + 4 \, a c d^{2}\right )}^{\frac{1}{4}} \sqrt{2 \, c d x + b d} + \sqrt{-b^{2} d^{2} + 4 \, a c d^{2}}\right ) + \frac{64}{3} \,{\left (2 \, c d x + b d\right )}^{\frac{3}{2}} c^{2} d^{5} + \frac{2 \,{\left (15 \,{\left (2 \, c d x + b d\right )}^{\frac{3}{2}} b^{4} c^{2} d^{9} - 120 \,{\left (2 \, c d x + b d\right )}^{\frac{3}{2}} a b^{2} c^{3} d^{9} + 240 \,{\left (2 \, c d x + b d\right )}^{\frac{3}{2}} a^{2} c^{4} d^{9} - 19 \,{\left (2 \, c d x + b d\right )}^{\frac{7}{2}} b^{2} c^{2} d^{7} + 76 \,{\left (2 \, c d x + b d\right )}^{\frac{7}{2}} a c^{3} d^{7}\right )}}{{\left (b^{2} d^{2} - 4 \, a c d^{2} -{\left (2 \, c d x + b d\right )}^{2}\right )}^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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